Is 945 a prime number?
It is possible to find out using mathematical methods whether a given integer is a prime number or not.
For 945, the answer is: No, 945 is not a prime number.
The list of all positive divisors (i.e., the list of all integers that divide 945) is as follows: 1, 3, 5, 7, 9, 15, 21, 27, 35, 45, 63, 105, 135, 189, 315, 945.
For 945 to be a prime number, it would have been required that 945 has only two divisors, i.e., itself and 1.
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Actually, one can immediately see that 945 cannot be prime, because 5 is one of its divisors: indeed, a number ending with 0 or 5 has necessarily 5 among its divisors. The last digit of 945 is 5, so it is divisible by 5 and is therefore not prime.
As a consequence:
- 945 is a multiple of 1
- 945 is a multiple of 3
- 945 is a multiple of 5
- 945 is a multiple of 7
- 945 is a multiple of 9
- 945 is a multiple of 15
- 945 is a multiple of 21
- 945 is a multiple of 27
- 945 is a multiple of 35
- 945 is a multiple of 45
- 945 is a multiple of 63
- 945 is a multiple of 105
- 945 is a multiple of 135
- 945 is a multiple of 189
- 945 is a multiple of 315
For 945 to be a prime number, it would have been required that 945 has only two divisors, i.e., itself and 1.
Is 945 a deficient number?
No, 945 is not a deficient number: to be deficient, 945 should have been such that 945 is larger than the sum of its proper divisors, i.e., the divisors of 945 without 945 itself (that is 1 + 3 + 5 + 7 + 9 + 15 + 21 + 27 + 35 + 45 + 63 + 105 + 135 + 189 + 315 = 975).
In fact, 945 is an abundant number; 945 is strictly smaller than the sum of its proper divisors (that is 1 + 3 + 5 + 7 + 9 + 15 + 21 + 27 + 35 + 45 + 63 + 105 + 135 + 189 + 315 = 975). The smallest abundant number is 12.