Is 943 a prime number?
It is possible to find out using mathematical methods whether a given integer is a prime number or not.
For 943, the answer is: No, 943 is not a prime number.
The list of all positive divisors (i.e., the list of all integers that divide 943) is as follows: 1, 23, 41, 943.
For 943 to be a prime number, it would have been required that 943 has only two divisors, i.e., itself and 1.
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As a consequence:
For 943 to be a prime number, it would have been required that 943 has only two divisors, i.e., itself and 1.
However, 943 is a semiprime (also called biprime or 2-almost-prime), because it is the product of a two non-necessarily distinct prime numbers. Indeed, 943 = 23 x 41, where 23 and 41 are both prime numbers.
Is 943 a deficient number?
Yes, 943 is a deficient number, that is to say 943 is a natural number that is strictly larger than the sum of its proper divisors, i.e., the divisors of 943 without 943 itself (that is 1 + 23 + 41 = 65).