Is 63 a prime number?
It is possible to find out using mathematical methods whether a given integer is a prime number or not.
For 63, the answer is: No, 63 is not a prime number.
The list of all positive divisors (i.e., the list of all integers that divide 63) is as follows: 1, 3, 7, 9, 21, 63.
For 63 to be a prime number, it would have been required that 63 has only two divisors, i.e., itself and 1.
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As a consequence:
- 63 is a multiple of 1
- 63 is a multiple of 3
- 63 is a multiple of 7
- 63 is a multiple of 9
- 63 is a multiple of 21
For 63 to be a prime number, it would have been required that 63 has only two divisors, i.e., itself and 1.
Is 63 a deficient number?
Yes, 63 is a deficient number, that is to say 63 is a natural number that is strictly larger than the sum of its proper divisors, i.e., the divisors of 63 without 63 itself (that is 1 + 3 + 7 + 9 + 21 = 41).