Is 936 a prime number?
It is possible to find out using mathematical methods whether a given integer is a prime number or not.
For 936, the answer is: No, 936 is not a prime number.
The list of all positive divisors (i.e., the list of all integers that divide 936) is as follows: 1, 2, 3, 4, 6, 8, 9, 12, 13, 18, 24, 26, 36, 39, 52, 72, 78, 104, 117, 156, 234, 312, 468, 936.
For 936 to be a prime number, it would have been required that 936 has only two divisors, i.e., itself and 1.
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As a consequence:
- 936 is a multiple of 1
- 936 is a multiple of 2
- 936 is a multiple of 3
- 936 is a multiple of 4
- 936 is a multiple of 6
- 936 is a multiple of 8
- 936 is a multiple of 9
- 936 is a multiple of 12
- 936 is a multiple of 13
- 936 is a multiple of 18
- 936 is a multiple of 24
- 936 is a multiple of 26
- 936 is a multiple of 36
- 936 is a multiple of 39
- 936 is a multiple of 52
- 936 is a multiple of 72
- 936 is a multiple of 78
- 936 is a multiple of 104
- 936 is a multiple of 117
- 936 is a multiple of 156
- 936 is a multiple of 234
- 936 is a multiple of 312
- 936 is a multiple of 468
For 936 to be a prime number, it would have been required that 936 has only two divisors, i.e., itself and 1.
Is 936 a deficient number?
No, 936 is not a deficient number: to be deficient, 936 should have been such that 936 is larger than the sum of its proper divisors, i.e., the divisors of 936 without 936 itself (that is 1 + 2 + 3 + 4 + 6 + 8 + 9 + 12 + 13 + 18 + 24 + 26 + 36 + 39 + 52 + 72 + 78 + 104 + 117 + 156 + 234 + 312 + 468 = 1 794).
In fact, 936 is an abundant number; 936 is strictly smaller than the sum of its proper divisors (that is 1 + 2 + 3 + 4 + 6 + 8 + 9 + 12 + 13 + 18 + 24 + 26 + 36 + 39 + 52 + 72 + 78 + 104 + 117 + 156 + 234 + 312 + 468 = 1 794). The smallest abundant number is 12.