Is 560 a prime number?
It is possible to find out using mathematical methods whether a given integer is a prime number or not.
For 560, the answer is: No, 560 is not a prime number.
The list of all positive divisors (i.e., the list of all integers that divide 560) is as follows: 1, 2, 4, 5, 7, 8, 10, 14, 16, 20, 28, 35, 40, 56, 70, 80, 112, 140, 280, 560.
For 560 to be a prime number, it would have been required that 560 has only two divisors, i.e., itself and 1.
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Actually, one can immediately see that 560 cannot be prime, because 5 is one of its divisors: indeed, a number ending with 0 or 5 has necessarily 5 among its divisors. The last digit of 560 is 0, so it is divisible by 5 and is therefore not prime.
As a consequence:
- 560 is a multiple of 1
- 560 is a multiple of 2
- 560 is a multiple of 4
- 560 is a multiple of 5
- 560 is a multiple of 7
- 560 is a multiple of 8
- 560 is a multiple of 10
- 560 is a multiple of 14
- 560 is a multiple of 16
- 560 is a multiple of 20
- 560 is a multiple of 28
- 560 is a multiple of 35
- 560 is a multiple of 40
- 560 is a multiple of 56
- 560 is a multiple of 70
- 560 is a multiple of 80
- 560 is a multiple of 112
- 560 is a multiple of 140
- 560 is a multiple of 280
For 560 to be a prime number, it would have been required that 560 has only two divisors, i.e., itself and 1.
Is 560 a deficient number?
No, 560 is not a deficient number: to be deficient, 560 should have been such that 560 is larger than the sum of its proper divisors, i.e., the divisors of 560 without 560 itself (that is 1 + 2 + 4 + 5 + 7 + 8 + 10 + 14 + 16 + 20 + 28 + 35 + 40 + 56 + 70 + 80 + 112 + 140 + 280 = 928).
In fact, 560 is an abundant number; 560 is strictly smaller than the sum of its proper divisors (that is 1 + 2 + 4 + 5 + 7 + 8 + 10 + 14 + 16 + 20 + 28 + 35 + 40 + 56 + 70 + 80 + 112 + 140 + 280 = 928). The smallest abundant number is 12.