Is 910 a prime number?
It is possible to find out using mathematical methods whether a given integer is a prime number or not.
For 910, the answer is: No, 910 is not a prime number.
The list of all positive divisors (i.e., the list of all integers that divide 910) is as follows: 1, 2, 5, 7, 10, 13, 14, 26, 35, 65, 70, 91, 130, 182, 455, 910.
For 910 to be a prime number, it would have been required that 910 has only two divisors, i.e., itself and 1.
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Actually, one can immediately see that 910 cannot be prime, because 5 is one of its divisors: indeed, a number ending with 0 or 5 has necessarily 5 among its divisors. The last digit of 910 is 0, so it is divisible by 5 and is therefore not prime.
As a consequence:
- 910 is a multiple of 1
- 910 is a multiple of 2
- 910 is a multiple of 5
- 910 is a multiple of 7
- 910 is a multiple of 10
- 910 is a multiple of 13
- 910 is a multiple of 14
- 910 is a multiple of 26
- 910 is a multiple of 35
- 910 is a multiple of 65
- 910 is a multiple of 70
- 910 is a multiple of 91
- 910 is a multiple of 130
- 910 is a multiple of 182
- 910 is a multiple of 455
For 910 to be a prime number, it would have been required that 910 has only two divisors, i.e., itself and 1.
Is 910 a deficient number?
No, 910 is not a deficient number: to be deficient, 910 should have been such that 910 is larger than the sum of its proper divisors, i.e., the divisors of 910 without 910 itself (that is 1 + 2 + 5 + 7 + 10 + 13 + 14 + 26 + 35 + 65 + 70 + 91 + 130 + 182 + 455 = 1 106).
In fact, 910 is an abundant number; 910 is strictly smaller than the sum of its proper divisors (that is 1 + 2 + 5 + 7 + 10 + 13 + 14 + 26 + 35 + 65 + 70 + 91 + 130 + 182 + 455 = 1 106). The smallest abundant number is 12.