Is 835 a prime number?
It is possible to find out using mathematical methods whether a given integer is a prime number or not.
For 835, the answer is: No, 835 is not a prime number.
The list of all positive divisors (i.e., the list of all integers that divide 835) is as follows: 1, 5, 167, 835.
For 835 to be a prime number, it would have been required that 835 has only two divisors, i.e., itself and 1.
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Actually, one can immediately see that 835 cannot be prime, because 5 is one of its divisors: indeed, a number ending with 0 or 5 has necessarily 5 among its divisors. The last digit of 835 is 5, so it is divisible by 5 and is therefore not prime.
As a consequence:
For 835 to be a prime number, it would have been required that 835 has only two divisors, i.e., itself and 1.
However, 835 is a semiprime (also called biprime or 2-almost-prime), because it is the product of a two non-necessarily distinct prime numbers. Indeed, 835 = 5 x 167, where 5 and 167 are both prime numbers.
Is 835 a deficient number?
Yes, 835 is a deficient number, that is to say 835 is a natural number that is strictly larger than the sum of its proper divisors, i.e., the divisors of 835 without 835 itself (that is 1 + 5 + 167 = 173).