Is 629 a prime number?
It is possible to find out using mathematical methods whether a given integer is a prime number or not.
For 629, the answer is: No, 629 is not a prime number.
The list of all positive divisors (i.e., the list of all integers that divide 629) is as follows: 1, 17, 37, 629.
For 629 to be a prime number, it would have been required that 629 has only two divisors, i.e., itself and 1.
Find out more:
As a consequence:
For 629 to be a prime number, it would have been required that 629 has only two divisors, i.e., itself and 1.
However, 629 is a semiprime (also called biprime or 2-almost-prime), because it is the product of a two non-necessarily distinct prime numbers. Indeed, 629 = 17 x 37, where 17 and 37 are both prime numbers.
Is 629 a deficient number?
Yes, 629 is a deficient number, that is to say 629 is a natural number that is strictly larger than the sum of its proper divisors, i.e., the divisors of 629 without 629 itself (that is 1 + 17 + 37 = 55).