Is 998013 a prime number?

998 013 is an odd number, because it is not evenly divisible by 2.

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• What is an even number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 998 013 is about 999.006.

Thus, the square root of 998 013 is not an integer, and therefore 998 013 is not a square number.

The square of a number (here 998 013) is the result of the product of this number (998 013) by itself (i.e., 998 013 × 998 013); the square of 998 013 is sometimes called "raising 998 013 to the power 2", or "998 013 squared".

The square of 998 013 is 996 029 948 169 because 998 013 × 998 013 = 998 013² = 996 029 948 169.

As a consequence, 998 013 is the square root of 996 029 948 169.

998 013 is a number with 6 digits.

The multiples of 998 013 are all integers evenly divisible by 998 013, that is all numbers such that the remainder of the division by 998 013 is zero. There are infinitely many multiples of 998 013. The smallest multiples of 998 013 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 998 013 too, since 0 × 998 013 = 0
• 998 013: indeed, 998 013 is a multiple of itself, since 998 013 is evenly divisible by 998 013 (we have 998 013 / 998 013 = 1, so the remainder of this division is indeed zero)
• 1 996 026: indeed, 1 996 026 = 998 013 × 2
• 2 994 039: indeed, 2 994 039 = 998 013 × 3
• 3 992 052: indeed, 3 992 052 = 998 013 × 4
• 4 990 065: indeed, 4 990 065 = 998 013 × 5
• etc.

• Preceding numbers: …998 011, 998 012
• Following numbers: 998 014, 998 015…

Nearest numbers from 998 013

• Preceding prime number: 998 009
• Following prime number: 998 017

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• 998 013 est-il un nombre premier ?