Is 997013 a prime number?

997 013 is an odd number, because it is not evenly divisible by 2.

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• What is an even number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 997 013 is about 998.505.

Thus, the square root of 997 013 is not an integer, and therefore 997 013 is not a square number.

Anyway, 997 013 is a prime number, and a prime number cannot be a perfect square.

The square of a number (here 997 013) is the result of the product of this number (997 013) by itself (i.e., 997 013 × 997 013); the square of 997 013 is sometimes called "raising 997 013 to the power 2", or "997 013 squared".

The square of 997 013 is 994 034 922 169 because 997 013 × 997 013 = 997 013² = 994 034 922 169.

As a consequence, 997 013 is the square root of 994 034 922 169.

997 013 is a number with 6 digits.

The multiples of 997 013 are all integers evenly divisible by 997 013, that is all numbers such that the remainder of the division by 997 013 is zero. There are infinitely many multiples of 997 013. The smallest multiples of 997 013 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 997 013 too, since 0 × 997 013 = 0
• 997 013: indeed, 997 013 is a multiple of itself, since 997 013 is evenly divisible by 997 013 (we have 997 013 / 997 013 = 1, so the remainder of this division is indeed zero)
• 1 994 026: indeed, 1 994 026 = 997 013 × 2
• 2 991 039: indeed, 2 991 039 = 997 013 × 3
• 3 988 052: indeed, 3 988 052 = 997 013 × 4
• 4 985 065: indeed, 4 985 065 = 997 013 × 5
• etc.

• Preceding numbers: …997 011, 997 012
• Following numbers: 997 014, 997 015…

Nearest numbers from 997 013

• Preceding prime number: 997 001
• Following prime number: 997 019

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• 997 013 est-il un nombre premier ?