It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 980 617 618 is not a prime number.
For example, 980 617 618 can be divided by 2: 980 617 618 / 2 = 490 308 809.
For 980 617 618 to be a prime number, it would have been required that 980 617 618 has only two divisors, i.e., itself and 1.
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980 617 618 is an even number, because it is evenly divisible by 2: 980 617 618 / 2 = 490 308 809.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 980 617 618 is about 31 314.815.
Thus, the square root of 980 617 618 is not an integer, and therefore 980 617 618 is not a square number.
The square of a number (here 980 617 618) is the result of the product of this number (980 617 618) by itself (i.e., 980 617 618 × 980 617 618); the square of 980 617 618 is sometimes called "raising 980 617 618 to the power 2", or "980 617 618 squared".
The square of 980 617 618 is 961 610 912 731 993 984 because 980 617 618 × 980 617 618 = 980 617 6182 = 961 610 912 731 993 984.
As a consequence, 980 617 618 is the square root of 961 610 912 731 993 984.
980 617 618 is a number with 9 digits.
The multiples of 980 617 618 are all integers evenly divisible by 980 617 618, that is all numbers such that the remainder of the division by 980 617 618 is zero. There are infinitely many multiples of 980 617 618. The smallest multiples of 980 617 618 are: