Is 980012 a prime number?

980 012 is an even number, because it is evenly divisible by 2: 980 012 / 2 = 490 006.

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• What is an even number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 980 012 is about 989.956.

Thus, the square root of 980 012 is not an integer, and therefore 980 012 is not a square number.

The square of a number (here 980 012) is the result of the product of this number (980 012) by itself (i.e., 980 012 × 980 012); the square of 980 012 is sometimes called "raising 980 012 to the power 2", or "980 012 squared".

The square of 980 012 is 960 423 520 144 because 980 012 × 980 012 = 980 012² = 960 423 520 144.

As a consequence, 980 012 is the square root of 960 423 520 144.

980 012 is a number with 6 digits.

The multiples of 980 012 are all integers evenly divisible by 980 012, that is all numbers such that the remainder of the division by 980 012 is zero. There are infinitely many multiples of 980 012. The smallest multiples of 980 012 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 980 012 too, since 0 × 980 012 = 0
• 980 012: indeed, 980 012 is a multiple of itself, since 980 012 is evenly divisible by 980 012 (we have 980 012 / 980 012 = 1, so the remainder of this division is indeed zero)
• 1 960 024: indeed, 1 960 024 = 980 012 × 2
• 2 940 036: indeed, 2 940 036 = 980 012 × 3
• 3 920 048: indeed, 3 920 048 = 980 012 × 4
• 4 900 060: indeed, 4 900 060 = 980 012 × 5
• etc.

• Preceding numbers: …980 010, 980 011
• Following numbers: 980 013, 980 014…

Nearest numbers from 980 012

• Preceding prime number: 979 987
• Following prime number: 980 027

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• 980 012 est-il un nombre premier ?