Is 9800 a prime number?

9 800 is an even number, because it is evenly divisible by 2: 9 800 / 2 = 4 900.

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• What is an even number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 9 800 is about 98.995.

Thus, the square root of 9 800 is not an integer, and therefore 9 800 is not a square number.

The square of a number (here 9 800) is the result of the product of this number (9 800) by itself (i.e., 9 800 × 9 800); the square of 9 800 is sometimes called "raising 9 800 to the power 2", or "9 800 squared".

The square of 9 800 is 96 040 000 because 9 800 × 9 800 = 9 800² = 96 040 000.

As a consequence, 9 800 is the square root of 96 040 000.

9 800 is a number with 4 digits.

The multiples of 9 800 are all integers evenly divisible by 9 800, that is all numbers such that the remainder of the division by 9 800 is zero. There are infinitely many multiples of 9 800. The smallest multiples of 9 800 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 9 800 too, since 0 × 9 800 = 0
• 9 800: indeed, 9 800 is a multiple of itself, since 9 800 is evenly divisible by 9 800 (we have 9 800 / 9 800 = 1, so the remainder of this division is indeed zero)
• 19 600: indeed, 19 600 = 9 800 × 2
• 29 400: indeed, 29 400 = 9 800 × 3
• 39 200: indeed, 39 200 = 9 800 × 4
• 49 000: indeed, 49 000 = 9 800 × 5
• etc.

• Preceding numbers: …9 798, 9 799
• Following numbers: 9 801, 9 802…

Nearest numbers from 9 800

• Preceding prime number: 9 791
• Following prime number: 9 803

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• 9 800 est-il un nombre premier ?