Is 942013 a prime number?

942 013 is an odd number, because it is not evenly divisible by 2.

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• What is an even number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 942 013 is about 970.574.

Thus, the square root of 942 013 is not an integer, and therefore 942 013 is not a square number.

Anyway, 942 013 is a prime number, and a prime number cannot be a perfect square.

The square of a number (here 942 013) is the result of the product of this number (942 013) by itself (i.e., 942 013 × 942 013); the square of 942 013 is sometimes called "raising 942 013 to the power 2", or "942 013 squared".

The square of 942 013 is 887 388 492 169 because 942 013 × 942 013 = 942 013² = 887 388 492 169.

As a consequence, 942 013 is the square root of 887 388 492 169.

942 013 is a number with 6 digits.

The multiples of 942 013 are all integers evenly divisible by 942 013, that is all numbers such that the remainder of the division by 942 013 is zero. There are infinitely many multiples of 942 013. The smallest multiples of 942 013 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 942 013 too, since 0 × 942 013 = 0
• 942 013: indeed, 942 013 is a multiple of itself, since 942 013 is evenly divisible by 942 013 (we have 942 013 / 942 013 = 1, so the remainder of this division is indeed zero)
• 1 884 026: indeed, 1 884 026 = 942 013 × 2
• 2 826 039: indeed, 2 826 039 = 942 013 × 3
• 3 768 052: indeed, 3 768 052 = 942 013 × 4
• 4 710 065: indeed, 4 710 065 = 942 013 × 5
• etc.

• Preceding numbers: …942 011, 942 012
• Following numbers: 942 014, 942 015…

Nearest numbers from 942 013

• Preceding prime number: 941 999
• Following prime number: 942 017

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• 942 013 est-il un nombre premier ?