It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 9 362 497 is not a prime number.
For example, 9 362 497 can be divided by 19: 9 362 497 / 19 = 492 763.
For 9 362 497 to be a prime number, it would have been required that 9 362 497 has only two divisors, i.e., itself and 1.
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9 362 497 is an odd number, because it is not evenly divisible by 2.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 9 362 497 is about 3 059.820.
Thus, the square root of 9 362 497 is not an integer, and therefore 9 362 497 is not a square number.
The square of a number (here 9 362 497) is the result of the product of this number (9 362 497) by itself (i.e., 9 362 497 × 9 362 497); the square of 9 362 497 is sometimes called "raising 9 362 497 to the power 2", or "9 362 497 squared".
The square of 9 362 497 is 87 656 350 075 009 because 9 362 497 × 9 362 497 = 9 362 4972 = 87 656 350 075 009.
As a consequence, 9 362 497 is the square root of 87 656 350 075 009.
The multiples of 9 362 497 are all integers evenly divisible by 9 362 497, that is all numbers such that the remainder of the division by 9 362 497 is zero. There are infinitely many multiples of 9 362 497. The smallest multiples of 9 362 497 are: