Is 933 a prime number?
It is possible to find out using mathematical methods whether a given integer is a prime number or not.
For 933, the answer is: No, 933 is not a prime number.
The list of all positive divisors (i.e., the list of all integers that divide 933) is as follows: 1, 3, 311, 933.
For 933 to be a prime number, it would have been required that 933 has only two divisors, i.e., itself and 1.
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As a consequence:
For 933 to be a prime number, it would have been required that 933 has only two divisors, i.e., itself and 1.
However, 933 is a semiprime (also called biprime or 2-almost-prime), because it is the product of a two non-necessarily distinct prime numbers. Indeed, 933 = 3 x 311, where 3 and 311 are both prime numbers.
Is 933 a deficient number?
Yes, 933 is a deficient number, that is to say 933 is a natural number that is strictly larger than the sum of its proper divisors, i.e., the divisors of 933 without 933 itself (that is 1 + 3 + 311 = 315).