Is 895 a prime number?
It is possible to find out using mathematical methods whether a given integer is a prime number or not.
For 895, the answer is: No, 895 is not a prime number.
The list of all positive divisors (i.e., the list of all integers that divide 895) is as follows: 1, 5, 179, 895.
For 895 to be a prime number, it would have been required that 895 has only two divisors, i.e., itself and 1.
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Actually, one can immediately see that 895 cannot be prime, because 5 is one of its divisors: indeed, a number ending with 0 or 5 has necessarily 5 among its divisors. The last digit of 895 is 5, so it is divisible by 5 and is therefore not prime.
As a consequence:
For 895 to be a prime number, it would have been required that 895 has only two divisors, i.e., itself and 1.
However, 895 is a semiprime (also called biprime or 2-almost-prime), because it is the product of a two non-necessarily distinct prime numbers. Indeed, 895 = 5 x 179, where 5 and 179 are both prime numbers.
Is 895 a deficient number?
Yes, 895 is a deficient number, that is to say 895 is a natural number that is strictly larger than the sum of its proper divisors, i.e., the divisors of 895 without 895 itself (that is 1 + 5 + 179 = 185).