Is 802 a prime number?
It is possible to find out using mathematical methods whether a given integer is a prime number or not.
For 802, the answer is: No, 802 is not a prime number.
The list of all positive divisors (i.e., the list of all integers that divide 802) is as follows: 1, 2, 401, 802.
For 802 to be a prime number, it would have been required that 802 has only two divisors, i.e., itself and 1.
Find out more:
As a consequence:
For 802 to be a prime number, it would have been required that 802 has only two divisors, i.e., itself and 1.
However, 802 is a semiprime (also called biprime or 2-almost-prime), because it is the product of a two non-necessarily distinct prime numbers. Indeed, 802 = 2 x 401, where 2 and 401 are both prime numbers.
Is 802 a deficient number?
Yes, 802 is a deficient number, that is to say 802 is a natural number that is strictly larger than the sum of its proper divisors, i.e., the divisors of 802 without 802 itself (that is 1 + 2 + 401 = 404).