It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 6 997 326 is not a prime number.
For example, 6 997 326 can be divided by 2: 6 997 326 / 2 = 3 498 663.
For 6 997 326 to be a prime number, it would have been required that 6 997 326 has only two divisors, i.e., itself and 1.
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6 997 326 is an even number, because it is evenly divisible by 2: 6 997 326 / 2 = 3 498 663.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 6 997 326 is about 2 645.246.
Thus, the square root of 6 997 326 is not an integer, and therefore 6 997 326 is not a square number.
The square of a number (here 6 997 326) is the result of the product of this number (6 997 326) by itself (i.e., 6 997 326 × 6 997 326); the square of 6 997 326 is sometimes called "raising 6 997 326 to the power 2", or "6 997 326 squared".
The square of 6 997 326 is 48 962 571 150 276 because 6 997 326 × 6 997 326 = 6 997 3262 = 48 962 571 150 276.
As a consequence, 6 997 326 is the square root of 48 962 571 150 276.
The multiples of 6 997 326 are all integers evenly divisible by 6 997 326, that is all numbers such that the remainder of the division by 6 997 326 is zero. There are infinitely many multiples of 6 997 326. The smallest multiples of 6 997 326 are: