Is 689 a prime number?
It is possible to find out using mathematical methods whether a given integer is a prime number or not.
For 689, the answer is: No, 689 is not a prime number.
The list of all positive divisors (i.e., the list of all integers that divide 689) is as follows: 1, 13, 53, 689.
For 689 to be a prime number, it would have been required that 689 has only two divisors, i.e., itself and 1.
Find out more:
As a consequence:
For 689 to be a prime number, it would have been required that 689 has only two divisors, i.e., itself and 1.
However, 689 is a semiprime (also called biprime or 2-almost-prime), because it is the product of a two non-necessarily distinct prime numbers. Indeed, 689 = 13 x 53, where 13 and 53 are both prime numbers.
Is 689 a deficient number?
Yes, 689 is a deficient number, that is to say 689 is a natural number that is strictly larger than the sum of its proper divisors, i.e., the divisors of 689 without 689 itself (that is 1 + 13 + 53 = 67).