Is 640 a prime number?
It is possible to find out using mathematical methods whether a given integer is a prime number or not.
For 640, the answer is: No, 640 is not a prime number.
The list of all positive divisors (i.e., the list of all integers that divide 640) is as follows: 1, 2, 4, 5, 8, 10, 16, 20, 32, 40, 64, 80, 128, 160, 320, 640.
For 640 to be a prime number, it would have been required that 640 has only two divisors, i.e., itself and 1.
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Actually, one can immediately see that 640 cannot be prime, because 5 is one of its divisors: indeed, a number ending with 0 or 5 has necessarily 5 among its divisors. The last digit of 640 is 0, so it is divisible by 5 and is therefore not prime.
As a consequence:
- 640 is a multiple of 1
- 640 is a multiple of 2
- 640 is a multiple of 4
- 640 is a multiple of 5
- 640 is a multiple of 8
- 640 is a multiple of 10
- 640 is a multiple of 16
- 640 is a multiple of 20
- 640 is a multiple of 32
- 640 is a multiple of 40
- 640 is a multiple of 64
- 640 is a multiple of 80
- 640 is a multiple of 128
- 640 is a multiple of 160
- 640 is a multiple of 320
For 640 to be a prime number, it would have been required that 640 has only two divisors, i.e., itself and 1.
Is 640 a deficient number?
No, 640 is not a deficient number: to be deficient, 640 should have been such that 640 is larger than the sum of its proper divisors, i.e., the divisors of 640 without 640 itself (that is 1 + 2 + 4 + 5 + 8 + 10 + 16 + 20 + 32 + 40 + 64 + 80 + 128 + 160 + 320 = 890).
In fact, 640 is an abundant number; 640 is strictly smaller than the sum of its proper divisors (that is 1 + 2 + 4 + 5 + 8 + 10 + 16 + 20 + 32 + 40 + 64 + 80 + 128 + 160 + 320 = 890). The smallest abundant number is 12.