Is 537 a prime number?
It is possible to find out using mathematical methods whether a given integer is a prime number or not.
For 537, the answer is: No, 537 is not a prime number.
The list of all positive divisors (i.e., the list of all integers that divide 537) is as follows: 1, 3, 179, 537.
For 537 to be a prime number, it would have been required that 537 has only two divisors, i.e., itself and 1.
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As a consequence:
For 537 to be a prime number, it would have been required that 537 has only two divisors, i.e., itself and 1.
However, 537 is a semiprime (also called biprime or 2-almost-prime), because it is the product of a two non-necessarily distinct prime numbers. Indeed, 537 = 3 x 179, where 3 and 179 are both prime numbers.
Is 537 a deficient number?
Yes, 537 is a deficient number, that is to say 537 is a natural number that is strictly larger than the sum of its proper divisors, i.e., the divisors of 537 without 537 itself (that is 1 + 3 + 179 = 183).