Is 398 a prime number?
It is possible to find out using mathematical methods whether a given integer is a prime number or not.
For 398, the answer is: No, 398 is not a prime number.
The list of all positive divisors (i.e., the list of all integers that divide 398) is as follows: 1, 2, 199, 398.
For 398 to be a prime number, it would have been required that 398 has only two divisors, i.e., itself and 1.
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As a consequence:
For 398 to be a prime number, it would have been required that 398 has only two divisors, i.e., itself and 1.
However, 398 is a semiprime (also called biprime or 2-almost-prime), because it is the product of a two non-necessarily distinct prime numbers. Indeed, 398 = 2 x 199, where 2 and 199 are both prime numbers.
Is 398 a deficient number?
Yes, 398 is a deficient number, that is to say 398 is a natural number that is strictly larger than the sum of its proper divisors, i.e., the divisors of 398 without 398 itself (that is 1 + 2 + 199 = 202).