Is 1993 a prime number?

1 993 is an odd number, because it is not evenly divisible by 2.

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• What is an even number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 1 993 is about 44.643.

Thus, the square root of 1 993 is not an integer, and therefore 1 993 is not a square number.

Anyway, 1 993 is a prime number, and a prime number cannot be a perfect square.

The square of a number (here 1 993) is the result of the product of this number (1 993) by itself (i.e., 1 993 × 1 993); the square of 1 993 is sometimes called "raising 1 993 to the power 2", or "1 993 squared".

The square of 1 993 is 3 972 049 because 1 993 × 1 993 = 1 993² = 3 972 049.

As a consequence, 1 993 is the square root of 3 972 049.

1 993 is a number with 4 digits.

The multiples of 1 993 are all integers evenly divisible by 1 993, that is all numbers such that the remainder of the division by 1 993 is zero. There are infinitely many multiples of 1 993. The smallest multiples of 1 993 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 1 993 too, since 0 × 1 993 = 0
• 1 993: indeed, 1 993 is a multiple of itself, since 1 993 is evenly divisible by 1 993 (we have 1 993 / 1 993 = 1, so the remainder of this division is indeed zero)
• 3 986: indeed, 3 986 = 1 993 × 2
• 5 979: indeed, 5 979 = 1 993 × 3
• 7 972: indeed, 7 972 = 1 993 × 4
• 9 965: indeed, 9 965 = 1 993 × 5
• etc.

• Preceding numbers: …1 991, 1 992
• Following numbers: 1 994, 1 995…

Nearest numbers from 1 993

• Preceding prime number: 1 987
• Following prime number: 1 997

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• 1 993 est-il un nombre premier ?