Is 118423 a prime number?

118 423 is an odd number, because it is not evenly divisible by 2.

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• What is an even number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 118 423 is about 344.126.

Thus, the square root of 118 423 is not an integer, and therefore 118 423 is not a square number.

Anyway, 118 423 is a prime number, and a prime number cannot be a perfect square.

The square of a number (here 118 423) is the result of the product of this number (118 423) by itself (i.e., 118 423 × 118 423); the square of 118 423 is sometimes called "raising 118 423 to the power 2", or "118 423 squared".

The square of 118 423 is 14 024 006 929 because 118 423 × 118 423 = 118 423² = 14 024 006 929.

As a consequence, 118 423 is the square root of 14 024 006 929.

118 423 is a number with 6 digits.

The multiples of 118 423 are all integers evenly divisible by 118 423, that is all numbers such that the remainder of the division by 118 423 is zero. There are infinitely many multiples of 118 423. The smallest multiples of 118 423 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 118 423 too, since 0 × 118 423 = 0
• 118 423: indeed, 118 423 is a multiple of itself, since 118 423 is evenly divisible by 118 423 (we have 118 423 / 118 423 = 1, so the remainder of this division is indeed zero)
• 236 846: indeed, 236 846 = 118 423 × 2
• 355 269: indeed, 355 269 = 118 423 × 3
• 473 692: indeed, 473 692 = 118 423 × 4
• 592 115: indeed, 592 115 = 118 423 × 5
• etc.

• Preceding numbers: …118 421, 118 422
• Following numbers: 118 424, 118 425…

Nearest numbers from 118 423

• Preceding prime number: 118 411
• Following prime number: 118 429