Is 115 a prime number?
It is possible to find out using mathematical methods whether a given integer is a prime number or not.
For 115, the answer is: No, 115 is not a prime number.
The list of all positive divisors (i.e., the list of all integers that divide 115) is as follows: 1, 5, 23, 115.
For 115 to be a prime number, it would have been required that 115 has only two divisors, i.e., itself and 1.
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Actually, one can immediately see that 115 cannot be prime, because 5 is one of its divisors: indeed, a number ending with 0 or 5 has necessarily 5 among its divisors. The last digit of 115 is 5, so it is divisible by 5 and is therefore not prime.
As a consequence:
For 115 to be a prime number, it would have been required that 115 has only two divisors, i.e., itself and 1.
However, 115 is a semiprime (also called biprime or 2-almost-prime), because it is the product of a two non-necessarily distinct prime numbers. Indeed, 115 = 5 x 23, where 5 and 23 are both prime numbers.
Is 115 a deficient number?
Yes, 115 is a deficient number, that is to say 115 is a natural number that is strictly larger than the sum of its proper divisors, i.e., the divisors of 115 without 115 itself (that is 1 + 5 + 23 = 29).