Is 113023 a prime number?

113 023 is an odd number, because it is not evenly divisible by 2.

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• What is an even number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 113 023 is about 336.189.

Thus, the square root of 113 023 is not an integer, and therefore 113 023 is not a square number.

Anyway, 113 023 is a prime number, and a prime number cannot be a perfect square.

The square of a number (here 113 023) is the result of the product of this number (113 023) by itself (i.e., 113 023 × 113 023); the square of 113 023 is sometimes called "raising 113 023 to the power 2", or "113 023 squared".

The square of 113 023 is 12 774 198 529 because 113 023 × 113 023 = 113 023² = 12 774 198 529.

As a consequence, 113 023 is the square root of 12 774 198 529.

113 023 is a number with 6 digits.

The multiples of 113 023 are all integers evenly divisible by 113 023, that is all numbers such that the remainder of the division by 113 023 is zero. There are infinitely many multiples of 113 023. The smallest multiples of 113 023 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 113 023 too, since 0 × 113 023 = 0
• 113 023: indeed, 113 023 is a multiple of itself, since 113 023 is evenly divisible by 113 023 (we have 113 023 / 113 023 = 1, so the remainder of this division is indeed zero)
• 226 046: indeed, 226 046 = 113 023 × 2
• 339 069: indeed, 339 069 = 113 023 × 3
• 452 092: indeed, 452 092 = 113 023 × 4
• 565 115: indeed, 565 115 = 113 023 × 5
• etc.

• Preceding numbers: …113 021, 113 022
• Following numbers: 113 024, 113 025…

Nearest numbers from 113 023

• Preceding prime number: 113 021
• Following prime number: 113 027

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• 113 023 est-il un nombre premier ?